Zavadovskiy Island
  Zavodovskiy Island Location off Antarctica | |
| Geography | |
|---|---|
| Location | Southern Ocean |
| Coordinates | 66°43′S 86°24′E / 66.717°S 86.400°ECoordinates: 66°43′S 86°24′E / 66.717°S 86.400°E |
| Highest elevation | 200 m (700 ft) |
| Demographics | |
| Population | uninhabited |
Zavadovskiy Island is an ice-covered island in the West Ice Shelf near Antarctica located at 66°43′S 86°24′E / 66.717°S 86.400°E. It rises to 200 meters (656 feet) and is located 12 miles east of Mikhaylov Island. It was discovered by the Soviet expedition of 1956 which named it for Ivan Zavadovskiy, second in command of the Imperial Russian Navy sloop-of-war Vostok in the Bellingshausen expedition in 1819-21.
This article incorporates public domain material from the United States Geological Survey document "Zavadovskiy Island" (content from the Geographic Names Information System).
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