United States presidential election in Vermont, 1888

United States presidential election in Vermont, 1888
Vermont
November 6, 1888

 
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 4 0
Popular vote 45,192 16,788
Percentage 69.05% 25.65%

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Vermont took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won Vermont by a margin of 43.40%.

Vice President-elect Levi P. Morton was born in Vermont. More specifically, in Shoreham.

Results

United States presidential election in Vermont, 1888[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 45,192 69.05% 4 100.00%
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 16,788 25.65% 0 0.00%
Labor Alson Streeter of Illinois Charles E. Cunningham of Arkansas 1,977 3.02% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 1,460 2.23% 0 0.00%
N/A Others Others 35 0.05% 0 0.00%
Total 65,452 100.00% 4 100.00%

References

  1. "1888 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved 23 December 2013.
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