United States presidential election in Vermont, 1884

United States presidential election in Vermont, 1884
Vermont
November 4, 1884

 
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 4 0
Popular vote 39,514 17,331
Percentage 66.52% 29.18%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Vermont took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won Vermont by a margin of 37.34%.

Results

United States presidential election in Vermont, 1884[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 39,514 66.52% 4 100.00%
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 17,331 29.18% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 1,753 2.95% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 1,753 2.95% 0 0.00%
N/A Others Others 18 0.03% 0 0.00%
Total 59,401 100.00% 4 100.00%

References

  1. "1884 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved 23 December 2013.
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