United States presidential election in Vermont, 1884
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The 1884 United States presidential election in Vermont took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Vermont voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won Vermont by a margin of 37.34%.
Results
United States presidential election in Vermont, 1884[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 39,514 | 66.52% | 4 | 100.00% | ||
Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 17,331 | 29.18% | 0 | 0.00% | ||
Prohibition | John Pierce St. John of Kansas | William Daniel of Maryland | 1,753 | 2.95% | 0 | 0.00% | ||
Greenback | Benjamin Franklin Butler of Massachusetts | Absolom Madden West of Mississippi | 1,753 | 2.95% | 0 | 0.00% | ||
N/A | Others | Others | 18 | 0.03% | 0 | 0.00% | ||
Total | 59,401 | 100.00% | 4 | 100.00% | ||||
References
- ↑ "1884 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved 23 December 2013.
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