United States presidential election in Rhode Island, 1868

United States presidential election in Rhode Island, 1868

November 3, 1868
Nominee Ulysses S. Grant Horatio Seymour Party Republican Democratic Home state Illinois New York Running mate Schuyler Colfax Francis Preston Blair, Jr. Electoral vote 4 0 Popular vote 12,993 6,548 Percentage 66.49% 33.51%
President before election Andrew Johnson Democratic Elected President Ulysses S. Grant Republican

Elections in Rhode Island
Federal government Presidential Elections 1792 1796 1800 1804 1808 1812 1816 1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential Primaries Democratic 2008 Republican 2008 2012 U.S. Senate elections 1970 1972 1976 1978 1982 1984 1988 1990 1994 1996 2000 2002 2006 2008 2012 2014 U.S. House elections 2006 2008 2010 2012 2014 2016
State government Gubernatorial Elections 1994 1998 2002 2006 2010 2014

The 1868 United States presidential election in Rhode Island took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Rhode Island voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 32.98%.

Results

References

State results of the 1868 U.S. presidential election
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