United States presidential election in Rhode Island, 1852

United States presidential election in Rhode Island, 1852

November 2, 1852
Nominee Franklin Pierce Winfield Scott Party Democratic Whig Home state New Hampshire New Jersey Running mate William R. King William Alexander Graham Electoral vote 4 0 Popular vote 8,735 7,626 Percentage 51.37% 44.85%
President before election Millard Fillmore Whig Elected President Franklin Pierce Democratic

Elections in Rhode Island
Federal government Presidential Elections 1792 1796 1800 1804 1808 1812 1816 1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential Primaries Democratic 2008 Republican 2008 2012 U.S. Senate elections 1970 1972 1976 1978 1982 1984 1988 1990 1994 1996 2000 2002 2006 2008 2012 2014 U.S. House elections 2006 2008 2010 2012 2014 2016
State government Gubernatorial Elections 1994 1998 2002 2006 2010 2014

The 1852 United States presidential election in Rhode Island took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Rhode Island voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a narrow margin of 6.52%.

Results

References

State results of the 1852 U.S. presidential election
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