United States presidential election in New Jersey, 1884

United States presidential election in New Jersey, 1884

November 4, 1884
Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 9 0 Popular vote 127,798 123,440 Percentage 48.98% 47.31%
President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

Elections in New Jersey
Federal government Presidential elections 1788-89 1792 1796 1800 1804 1808 1812 1816 1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Primary elections Democratic 2004 2008 Republican 2008 2012 United States Senate elections 1982 1984 1988 1990 1994 1996 2000 2002 2006 2008 2012 2013 2014 Congressional elections 1798 2006 5th 13th 2008 7th 2010 2012 2014 2016 2018 Special elections At-large, 1795 At-large, 1808 At-large, 1810 At-large, 1814 At-large, 1821 At-large, 1828 10th district, 2012
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The 1884 United States presidential election in New Jersey took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won his birth state by a very narrow margin of 1.67%.

Results

References