United States presidential election in Massachusetts, 1896

United States presidential election in Massachusetts, 1896
Massachusetts
November 3, 1896

 
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 15 0
Popular vote 278,976 105,711
Percentage 69.47% 26.32%

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Massachusetts took place on November 3, 1896. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Massachusetts overwhelmingly voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won Massachusetts by a margin of 43.15%.

Results

United States presidential election in Massachusetts, 1896[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William McKinley of Ohio Garret Hobart of New Jersey 278,976 69.47% 15 100.00%
Democratic William Jennings Bryan of Nebraska Arthur Sewall of Maine 105,711 26.32% 0 0.00%
National Democratic John McAuley Palmer of Illinois Simon Bolivar Buckner of Kentucky 11,749 2.93% 0 0.00%
Prohibition Joshua Levering of Maryland Hale Johnson of Illinois 2,998 0.75% 0 0.00%
Socialist Labor Charles Horatio Matchett of New York Matthew Maguire of New Jersey 2,114 0.53% 0 0.00%
N/A Others Others 20 0.01% 0 0.00%
Total 401,568 100.00% 15 100.00%

References

  1. "1896 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.
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