United States presidential election in Louisiana, 1836

November 3 – December 7, 1836


Nominee	Martin Van Buren	Hugh White
Party	Democratic	Whig
Home state	New York	Tennessee
Running mate	Richard Johnson	John Tyler
Electoral vote	5	0
Popular vote	3,842	3,583
Percentage	51.74%	48.26%

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

Elections in Louisiana

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Government

The 1836 United States presidential election in Louisiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Louisiana voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Louisiana by a margin of 3.48%.

Results

United States presidential election in Louisiana, 1836^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	3,842	51.74%	5
	Whig	Hugh White	3,583	48.26%	0
Totals			7,425	100.0%	5

References

↑ "1836 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved 4 August 2012.

State Results of the 1836 U.S. presidential election
Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum
General articles	Election timeline
Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia
Other 1836 elections	House Senate Gubernatorial

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