United States presidential election in Idaho, 1992

United States presidential election in Idaho, 1992

November 3, 1992
Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 4 0 0 Popular vote 202,645 137,013 130,395 Percentage 42.0% 28.4% 27.1%
County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%
President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

Elections in Idaho
Federal government Presidential elections 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential primaries Democratic Caucuses 2008 Republican Primaries 2008 2012 U.S. Senate elections 1980 1986 1990 1992 1996 1998 2002 2004 2008 2010 2014 U.S. House elections 2006 2008 2010 2012 2014
State government General elections 2014 Gubernatorial elections 1986 1990 1994 1998 2002 2006 2010 2014 State legislature elections 2006
Ballot measures Gubernatorial elections Amendment 2 Proposition 2

The 1992 United States presidential election in Idaho took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Idaho was won by incumbent President George H.W. Bush (R-Texas) with 42.03% of the popular vote over Governor Bill Clinton (D-Arkansas) with 28.42%. Businessman Ross Perot (I-Texas) finished in a close third with 27.05% of the popular vote.^[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.^[2]

Results

References