United States presidential election in Connecticut, 1860
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| Elections in Connecticut | ||||||||
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The 1860 United States presidential election in Connecticut took place on November 2, 1860 throughout all 33 states which was part of the 1860 United States presidential election. Voters chose six electors of the Electoral College, who voted for President and Vice President.
Connecticut was won by Republican candidate Abraham Lincoln, who won by a margin of 32.36%.
Results
| United States presidential election in Connecticut, 1860[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 43,486 | 53.86% | 6 | 100.00% | ||
| Democratic | Stephen A. Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 17,364 | 21.50% | 0 | 0.00% | ||
| Southern Democratic | John C. Breckinridge of Kentucky | Joseph Lane of Oregon | 16,558 | 20.51% | 0 | 0.00% | ||
| Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 3,337 | 4.13% | 0 | 0.00% | ||
| Total | 80,745 | 100.00% | 6 | 100.00% | ||||
References
- ↑ "1860 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 24 December 2013.
State results of the 1860 U.S. presidential election | ||
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