United States presidential election in Arkansas, 1836

United States presidential election in Arkansas, 1836

November 3 – December 7, 1836
Nominee Martin Van Buren Hugh White Party Democratic Whig Home state New York Tennessee Running mate Richard Johnson John Tyler Electoral vote 3 0 Popular vote 2,380 1,334 Percentage 64.08% 35.92%
President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

Elections in Arkansas
Federal government Presidential elections 1836 1840 1844 1848 1852 1856 1860 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential primaries Democratic 2008 Republican 2008 2012 U.S. Senate elections 1980 1984 1986 1990 1992 1996 1998 2002 2004 2008 2010 2014 2016 U.S. House elections 2000 2002 2004 2006 2008 2010 2012 2014 2016 Special elections 3rd District, 2001
State government Gubernatorial elections 1958 1966 1978 1980 1982 1984 1986 1990 1994 1998 2002 2006 2010 2014 State elections 2000 2002 2004 2006 2008 2010 2012 2014
Ballot measures 2004 Constitutional Amendment 3 2008 Proposed Initiative Act No. 1

The 1836 United States presidential election in Arkansas took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Arkansas voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Arkansas by a margin of 28.16%.

Results

References