Suchodół, Węgrów County
| Suchodół | |
|---|---|
| Village | |
  Suchodół | |
| Coordinates: 52°19′N 21°56′E / 52.317°N 21.933°E | |
| Country |
 Poland |
| Voivodeship | Masovian |
| County | Węgrów |
| Gmina | Grębków |
Suchodół [suˈxɔduu̯] is a village in the administrative district of Gmina Grębków, within Węgrów County, Masovian Voivodeship, in east-central Poland.[1] It lies approximately 6 kilometres (4 mi) north of Grębków, 11 km (7 mi) south-west of Węgrów, and 65 km (40 mi) east of Warsaw.
References
Coordinates: 52°19′00″N 21°56′00″E / 52.3167°N 21.9333°E
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