Stevenson Island (Wyoming)

Stevenson Island (Wyoming)
Stevenson Island (Wyoming)
Geography
Location Wyoming
Coordinates 44°30′50″N 110°23′02″W / 44.514°N 110.384°W / 44.514; -110.384Coordinates: 44°30′50″N 110°23′02″W / 44.514°N 110.384°W / 44.514; -110.384
Total islands 1
Highest elevation 2,366 m (7,762 ft)
Administration
Demographics
Population 0

Stevenson Island is a small, uninhabited island in Yellowstone Lake, Teton County, Wyoming.[1] It was originally called Stevenson's Island[2] after Colonel James D. Stevenson,[3] and is now sometimes called Stevensons Island.[4]

The island is long and narrow, lying in a generally north-south orientation. At the widest, it is about 250 metres (820 ft), and the length is about 1,800 metres (1.1 mi) long.[5] It is about 2.5 kilometres (1.6 mi) from the west shore of Yellowstone Lake, where Weasel Creek enters the lake.[6]

Stevenson Island in 1976

See also

References

  1. ↑ mytopo.com. "Find a Map > States > Wyoming > Teton County > Island > Stevenson Island." Accessed 29-Mar-2013.
  2. ↑ Yellowstone Lake : Pre-park era exploration. The article has a correspondence to Assistant Secretary of the Smithsonian Institution with the name "Stevenson's Island," dated August 8th, 1871. Accessed 29-Mar-2013.
  3. ↑ Writers' Program, Wyoming. "Wyoming: A Guide to Its History, Highways, and People." University of Nebraska Press, 1981. ISBN 0-8032-1958-X.
  4. ↑ "Stevenson Island". Geographic Names Information System. United States Geological Survey. Accessed 29-Mar-2013.
  5. ↑ bing.com/maps "Stevenson Island, WY". Accessed 29-Mar-2013.
  6. ↑ mytopo.com. "Find a Map > States > Wyoming > USGS Quad Maps > Lake". Accessed 29-Mar-2013.
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