Sherman Township, Kearney County, Nebraska
Sherman Township | |
---|---|
Township | |
Location in Kearney County | |
Coordinates: 40°23′40″N 099°00′30″W / 40.39444°N 99.00833°WCoordinates: 40°23′40″N 099°00′30″W / 40.39444°N 99.00833°W | |
Country | United States |
State | Nebraska |
County | Kearney |
Area | |
• Total | 36.04 sq mi (93.34 km2) |
• Land | 36 sq mi (93.25 km2) |
• Water | 0.04 sq mi (0.09 km2) 0.1% |
Elevation | 2,172 ft (662 m) |
Population (2000) | |
• Total | 97 |
• Density | 2.7/sq mi (1/km2) |
GNIS feature ID | 0838249 |
Sherman Township is one of fourteen townships in Kearney County, Nebraska, United States. The population was 97 at the 2000 census. A 2006 estimate placed the township's population at 93.[1]
See also
References
- ↑ "Subcounty population estimates: Nebraska 2000-2006" (CSV). United States Census Bureau, Population Division. 2007-06-28. Retrieved 2008-02-25.
External links
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