First inauguration of Grover Cleveland
Cleveland delivering his inaugural address. | |
Date | March 4, 1885 |
---|---|
Location |
Washington, D.C. United States Capitol |
Participants |
President Grover Cleveland Vice President Thomas A. Hendricks |
The first inauguration of Grover Cleveland as the 22nd President of the United States was held on March 4, 1885, at the eastern portico of the United States Capitol in Washington, D.C.. The inauguration marked the commencement of the first four-year term of Grover Cleveland as President and the only term of Thomas A. Hendricks as Vice President. Hendricks died 266 days into this term, and the office remained vacant for the balance of it. (Prior to ratification of the Twenty-fifth Amendment in 1967, no constitutional provision existed for filling an intra-term vacancy in the vice presidency.)
Chief Justice Morrison R. Waite administered the presidential oath of office, and Cleveland held a Bible given to him at age 15 by his mother as he recited it. Cleveland's second inauguration took place eight years after the first, as his two terms in office were not consecutive. He is the only U.S. president to serve non-consecutive terms.[1]
See also
- Presidency of Grover Cleveland
- Second inauguration of Grover Cleveland
- United States presidential election, 1884
References
- ↑ "Archived copy". Archived from the original on 2009-01-20. Retrieved 2009-01-22.
External links
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