Douglas Township, Saunders County, Nebraska

Douglas Township
Township

Location in Saunders County
Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W / 41.35167; -96.73694Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W / 41.35167; -96.73694
Country United States
State Nebraska
County Saunders
Area
 • Total 32.01 sq mi (82.91 km2)
 • Land 32.01 sq mi (82.91 km2)
 • Water 0 sq mi (0 km2)  0%
Elevation 1,309 ft (399 m)
Population (2000)
 • Total 196
 • Density 6.1/sq mi (2.4/km2)
GNIS feature ID 0837967

Douglas Township is one of twenty-four townships in Saunders County, Nebraska, United States. The population was 196 at the 2000 census. A 2006 estimate placed the township's population at 205.[1]

See also

References

  1. ↑ "Subcounty population estimates: Nebraska 2000-2006". United States Census Bureau, Population Division. 2007-06-28. Archived from the original (CSV) on 2008-02-18. Retrieved 2008-03-04.


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