Deerfield Township, Ross County, Ohio

Deerfield Township, Ross County, Ohio
Township


Location of Deerfield Township in Ross County
Coordinates: 39°29′52″N 83°9′7″W / 39.49778°N 83.15194°W / 39.49778; -83.15194Coordinates: 39°29′52″N 83°9′7″W / 39.49778°N 83.15194°W / 39.49778; -83.15194
Country United States
State Ohio
County Ross
Area
  Total 30.8 sq mi (79.7 km2)
  Land 30.8 sq mi (79.7 km2)
  Water 0.0 sq mi (0.0 km2)
Elevation[1] 732 ft (223 m)
Population (2000)
  Total 1,096
  Density 35.6/sq mi (13.7/km2)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
FIPS code 39-21224[2]
GNIS feature ID 1086894[1]

Deerfield Township is one of the sixteen townships of Ross County, Ohio, United States. The 2000 census found 1,096 people in the township, 580 of whom lived in the unincorporated portions of the township.[3]

Geography

Located in the northwestern corner of the county, it borders the following townships:

The village of Clarksburg is located in northern Deerfield Township.

Name and history

Statewide, other Deerfield Townships are located in Morgan, Portage, and Warren counties.

Government

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[4] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.

References

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