Incircle and excircles of a triangle

A triangle (black) with incircle (blue), incenter (I), excircles (orange), excenters (J_A,J_B,J_C), internal angle bisectors (red) and external angle bisectors (green). The green triangle is the excentral triangle.

In geometry, the incircle or inscribed circle of a triangle is the largest circle contained in the triangle; it touches (is tangent to) the three sides. The center of the incircle is a triangle center called the triangle's incenter.^[1]

An excircle or escribed circle^[2] of the triangle is a circle lying outside the triangle, tangent to one of its sides and tangent to the extensions of the other two. Every triangle has three distinct excircles, each tangent to one of the triangle's sides.^[3]

The center of the incircle, called the incenter, can be found as the intersection of the three internal angle bisectors.^[3]^[4] The center of an excircle is the intersection of the internal bisector of one angle (at vertex A, for example) and the external bisectors of the other two. The center of this excircle is called the excenter relative to the vertex A, or the excenter of A.^[3] Because the internal bisector of an angle is perpendicular to its external bisector, it follows that the center of the incircle together with the three excircle centers form an orthocentric system.^[5]^{:p. 182}

Polygons with more than three sides do not all have an incircle tangent to all sides; those that do are called tangential polygons. See also Tangent lines to circles.

Incircle and incenter

Suppose $\triangle ABC$ has an incircle with radius r and center I. Let a be the length of BC, b the length of AC, and c the length of AB And let $T_{a},T_{b},{\text{ and }}T_{c}$ be the touchpoints where the incircle touches BC , AC and AB

Incenter

The incenter is the point where the internal angle bisectors of $\angle ABC,\angle BCA,{\text{ and }}\angle BAC$ meet.

The distance from vertex A to the incenter I is:

$d(A,I)=c{\frac {\sin({\frac {1}{2}}\angle B)}{\cos({\frac {1}{2}}\angle C)}}=b{\frac {\sin({\frac {1}{2}}\angle C)}{\cos({\frac {1}{2}}\angle B)}}$

Trilinear coordinates of the incenter

The trilinear coordinates for a point in the triangle is the ratio of distances to the triangle sides. Because the Incenter is the same distance of all sides the trilinear coordinates for the incenter are ^[6]

\ 1:1:1.

Barycentric coordinates of the incenter

The barycentric coordinates for a point in a triangle give weights such that the point is the weighted average of the triangle vertex positions. Barycentric coordinates for the incenter are given by

\ a:b:c

where $a$ , $b$ , and $c$ are the lengths of the sides of the triangle, or equivalently (using the law of sines) by

\sin(A):\sin(B):\sin(C)

where $A$ , $B$ , and $C$ are the angles at the three vertices.

Cartesian coordinates of the incenter

The Cartesian coordinates of the incenter are a weighted average of the coordinates of the three vertices using the side lengths of the triangle relative to the perimeter—i.e., using the barycentric coordinates given above, normalized to sum to unity—as weights. (The weights are positive so the incenter lies inside the triangle as stated above.) If the three vertices are located at $(x_{a},y_{a})$ , $(x_{b},y_{b})$ , and $(x_c,y_c)$ , and the sides opposite these vertices have corresponding lengths $a$ , $b$ , and $c$ , then the incenter is at

{\bigg (}{\frac {ax_{a}+bx_{b}+cx_{c}}{a+b+c}},{\frac {ay_{a}+by_{b}+cy_{c}}{a+b+c}}{\bigg )}={\frac {a(x_{a},y_{a})+b(x_{b},y_{b})+c(x_{c},y_{c})}{a+b+c}}.

Distances from the incenter to the vertices

Denoting the incenter of triangle ABC as I, the distances from the incenter to the vertices combined with the lengths of the triangle sides obey the equation^[7]

{\frac {IA\cdot IA}{CA\cdot AB}}+{\frac {IB\cdot IB}{AB\cdot BC}}+{\frac {IC\cdot IC}{BC\cdot CA}}=1.

Additionally,^[8]

IA\cdot IB\cdot IC=4Rr^{2},

where R and r are the triangle's circumradius and inradius respectively.

Other incenter properties

The collection of triangle centers may be given the structure of a group under coordinate-wise multiplication of trilinear coordinates; in this group, the incenter forms the identity element.^[6]

Incircle and its radius properties

Distances between vertex and nearest touchpoints

The distances from a vertex to the two nearest touchpoints are equal:

d(A,T_{B})=d(A,T_{C}))={\frac {1}{2}}(b+c-a)

Other incircle properties

Suppose the tangency points of the incircle divide the sides into lengths of x and y, y and z, and z and x. Then the incircle has the radius^[9]

r={\sqrt {\frac {xyz}{x+y+z}}}

and the area of the triangle is

\Delta ={\sqrt {xyz(x+y+z)}}.

If the altitudes from sides of lengths a, b, and c are h_a, h_b, and h_c then the inradius r is one-third of the harmonic mean of these altitudes, i.e.

r={\frac {1}{h_{a}^{-1}+h_{b}^{-1}+h_{c}^{-1}}}.

The product of the incircle radius r and the circumcircle radius R of a triangle with sides a, b, and c is^[5]^{:p. 189, #298(d)}

rR={\frac {abc}{2(a+b+c)}}.

Some relations among the sides, incircle radius, and circumcircle radius are:^[10]

ab+bc+ca=s^{2}+(4R+r)r,

a^{2}+b^{2}+c^{2}=2s^{2}-2(4R+r)r.

Any line through a triangle that splits both the triangle's area and its perimeter in half goes through the triangle's incenter (the center of its incircle). There are either one, two, or three of these for any given triangle.^[11]

Denoting the center of the incircle of triangle ABC as I, we have^[12]

{\frac {IA\cdot IA}{CA\cdot AB}}+{\frac {IB\cdot IB}{AB\cdot BC}}+{\frac {IC\cdot IC}{BC\cdot CA}}=1

and^[13]^:p.121,#84

IA\cdot IB\cdot IC=4Rr^{2}.

The distance from any vertex to the incircle tangency on either adjacent side is half the sum of the vertex's adjacent sides minus half the opposite side.^[14] Thus for example for vertex B and adjacent tangencies T_A and TC,

BT_{A}=BT_{C}={\frac {BC+AB-AC}{2}}.

The incircle radius is no greater than one-ninth the sum of the altitudes.^[15]^{:p. 289}

The squared distance from the incenter I to the circumcenter O is given by^[16]^:p.232

OI^{2}=R(R-2r),

and the distance from the incenter to the center N of the nine point circle is^[16]^:p.232

IN={\frac {1}{2}}(R-2r)<{\frac {1}{2}}R.

The incenter lies in the medial triangle (whose vertices are the midpoints of the sides).^[16]^{:p.233, Lemma 1}

Relation to area of the triangle

The radii of the incircle is related to the area of the triangle.^[17] The ratio of the area of the incircle to the area of the triangle is less than or equal to ${\frac {\pi }{3{\sqrt {3}}}}$ , with equality holding only for equilateral triangles.^[18]

Suppose $\triangle ABC$ has an incircle with radius r and center I. Let a be the length of BC, b the length of AC, and c the length of AB. Now, the incircle is tangent to AB at some point C′, and so $\angle AT_{c}I$ is right. Thus the radius T_cI is an altitude of $\triangle IAB$ . Therefore, $\triangle IAB$ has base length c and height r, and so has area ${\tfrac {1}{2}}cr$ . Similarly, $\triangle IAC$ has area ${\tfrac {1}{2}}br$ and $\triangle IBC$ has area ${\tfrac {1}{2}}ar$ . Since these three triangles decompose $\triangle ABC$ , we see that the area $\Delta {\text{ of }}\triangle ABC$ is:

\Delta ={\frac {1}{2}}(a+b+c)r=sr,

and

r={\frac {\Delta }{s}},

where $\Delta$ is the area of $\triangle ABC$ and $s={\frac {1}{2}}(a+b+c)$ is its semiperimeter.

For an alternative formula, consider $\triangle IT_{c}A$ . This is a right-angled triangle with one side equal to r and the other side equal to $r\cot {\frac {\angle A}{2}}$ . The same is true for $\triangle IB'A$ . The large triangle is composed of 6 such triangles and the total area is:

\Delta =r^{2}\cdot (\cot {\frac {\angle A}{2}}+\cot {\frac {\angle B}{2}}+\cot {\frac {\angle C}{2}})

Gergonne triangle and point

The Gergonne triangle (of ABC) is defined by the 3 touchpoints of the incircle on the 3 sides. The touchpoint opposite A is denoted T_A, etc.

This Gergonne triangle T_AT_BT_C is also known as the contact triangle or intouch triangle of ABC. Its area is

K_{T}=K{\frac {2r^{2}s}{abc}}

where $K$ , $r$ , $s$ are the area, radius of the incircle and semiperimeter of the original triangle, and $a$ , $b$ , $c$ are the side lengths of the original triangle. This is the same area as that of the extouch triangle.^[19]

The three lines AT_A, BT_B and CT_C intersect in a single point called the Gergonne point, denoted as Ge - X(7). The Gergonne point lies in the open orthocentroidal disk punctured at its own center, and could be any point therein.^[20]

Interestingly, the Gergonne point of a triangle is the symmedian point of the Gergonne triangle. For a full set of properties of the Gergonne point see.^[21]

Trilinear coordinates for the vertices of the intouch triangle are given by

${\text{vertex}}\,T_{A}=0:\sec ^{2}\left({\frac {B}{2}}\right):\sec ^{2}\left({\frac {C}{2}}\right)$
${\text{vertex}}\,T_{B}=\sec ^{2}\left({\frac {A}{2}}\right):0:\sec ^{2}\left({\frac {C}{2}}\right)$
${\text{vertex}}\,T_{C}=\sec ^{2}\left({\frac {A}{2}}\right):\sec ^{2}\left({\frac {B}{2}}\right):0$

Trilinear coordinates for the Gergonne point are given by

\sec ^{2}\left({\frac {A}{2}}\right):\sec ^{2}\left({\frac {B}{2}}\right):\sec ^{2}\left({\frac {C}{2}}\right)

or, equivalently, by the Law of Sines,

{\frac {bc}{b+c-a}}:{\frac {ca}{c+a-b}}:{\frac {ab}{a+b-c}}

Excircles and excenters

An excircle or escribed circle^[22] of the triangle is a circle lying outside the triangle, tangent to one of its sides and tangent to the extensions of the other two. Every triangle has three distinct excircles, each tangent to one of the triangle's sides.^[3]

The center of an excircle is the intersection of the internal bisector of one angle (at vertex A, for example) and the external bisectors of the other two. The center of this excircle is called the excenter relative to the vertex A, or the excenter of A.^[3] Because the internal bisector of an angle is perpendicular to its external bisector, it follows that the center of the incircle together with the three excircle centers form an orthocentric system.^[5]^{:p. 182}

Trilinear coordinates of excenters

While A triangle's incenter has trilinear coordinates $1:1:1.$ Its excenters (the centers of its excircles) have trilinears $-1:1:1$ , $1:-1:1$ and $1:1:-1.$

Exradii

The radii of the excircles are called the exradii.

the exradius of the Excircle opposite A (so touching BC, centered at $J_{A}$ is

r_{a}={\sqrt {\frac {s(s-b)(s-c)}{s-a}}}.

^[23]

where $s={\frac {1}{2}}(a+b+c)$

Derivation of exradii formula

Let the excircle at side AB touch at side AC extended at G, and let this excircle's radius be $r_{c}$ and its center be $J_{c}$ .

Then $J_{c}G$ is an altitude of $\triangle ACJ_{c}$ , so $\triangle ACJ_{c}$ has area ${\tfrac {1}{2}}br_{c}$ . By a similar argument, $\triangle BCJ_{c}$ has area ${\tfrac {1}{2}}ar_{c}$ and $\triangle ABJ_{c}$ has area ${\tfrac {1}{2}}cr_{c}$ . Thus the area $\Delta$ of triangle $\triangle ABC$ is

\Delta ={\frac {1}{2}}(a+b-c)r_{c}=(s-c)r_{c}

So, by symmetry, denoting $r$ as the radius of the incircle,

\Delta =sr=(s-a)r_{a}=(s-b)r_{b}=(s-c)r_{c}

By the Law of Cosines, we have

\cos A={\frac {b^{2}+c^{2}-a^{2}}{2bc}}

Combining this with the identity $\sin ^{2}A+\cos ^{2}A=1$ , we have

\sin A={\frac {\sqrt {-a^{4}-b^{4}-c^{4}+2a^{2}b^{2}+2b^{2}c^{2}+2a^{2}c^{2}}}{2bc}}

But $\Delta ={\tfrac {1}{2}}bc\sin A$ , and so

{\begin{aligned}\Delta &={\frac {1}{4}}{\sqrt {-a^{4}-b^{4}-c^{4}+2a^{2}b^{2}+2b^{2}c^{2}+2a^{2}c^{2}}}\\&={\frac {1}{4}}{\sqrt {(a+b+c)(-a+b+c)(a-b+c)(a+b-c)}}\\&={\sqrt {s(s-a)(s-b)(s-c)}},\end{aligned}}

which is Heron's formula.

Combining this with $sr=\Delta$ , we have

r^{2}={\frac {\Delta ^{2}}{s^{2}}}={\frac {(s-a)(s-b)(s-c)}{s}}.

Similarly, $(s-a)r_{a}=\Delta$ gives

r_{a}^{2}={\frac {s(s-b)(s-c)}{s-a}}

and

r_{a}={\sqrt {\frac {s(s-b)(s-c)}{s-a}}}.

^[24]

Other exradii properties

From the formulas above one can see that the excircles are always larger than the incircle and that the largest excircle is the one tangent to the longest side and the smallest excircle is tangent to the shortest side. Further, combining these formulas yields:^[25]

\Delta ={\sqrt {rr_{a}r_{b}r_{c}}}.

The ratio of the area of the incircle to the area of the triangle is less than or equal to ${\frac {\pi }{3{\sqrt {3}}}}$ , with equality holding only for equilateral triangles.^[26]

Other excircle properties

The circular hull of the excircles is internally tangent to each of the excircles, and thus is an Apollonius circle.^[27] The radius of this Apollonius circle is ${\frac {r^{2}+s^{2}}{4r}}$ where r is the incircle radius and s is the semiperimeter of the triangle.^[28]

The following relations hold among the inradius r, the circumradius R, the semiperimeter s, and the excircle radii r_a, r_b, r_c:^[10]

r_{a}+r_{b}+r_{c}=4R+r,

r_{a}r_{b}+r_{b}r_{c}+r_{c}r_{a}=s^{2},

r_{a}^{2}+r_{b}^{2}+r_{c}^{2}=(4R+r)^{2}-2s^{2},

The circle through the centers of the three excircles has radius 2R.^[10]

If H is the orthocenter of triangle ABC, then^[10]

r_{a}+r_{b}+r_{c}+r=AH+BH+CH+2R,

r_{a}^{2}+r_{b}^{2}+r_{c}^{2}+r^{2}=AH^{2}+BH^{2}+CH^{2}+(2R)^{2}.

Nagel triangle and Nagel point

The Nagel triangle or extouch triangle of ABC is denoted by the vertices T_A, T_B and T_C that are the three points where the excircles touch the reference triangle ABC and where T_A is opposite of A, etc. This triangle T_AT_BT_C is also known as the extouch triangle of ABC. The circumcircle of the extouch triangle T_AT_BT_C is called the Mandart circle.

The three lines AT_A, BT_B and CT_C are called the splitters of the triangle; they each bisect the perimeter of the triangle,

$AB+BT_{A}=AC+CT_{A}={\frac {1}{2}}\left(AB+BC+AC\right)$

The splitters intersect in a single point, the triangle's Nagel point Na - X(8).

Trilinear coordinates for the vertices of the extouch triangle are given by

${\text{vertex}}\,T_{A}=0:\csc ^{2}\left({\frac {B}{2}}\right):\csc ^{2}\left({\frac {C}{2}}\right)$
${\text{vertex}}\,T_{B}=\csc ^{2}\left({\frac {A}{2}}\right):0:\csc ^{2}\left({\frac {C}{2}}\right)$
${\text{vertex}}\,T_{C}=\csc ^{2}\left({\frac {A}{2}}\right):\csc ^{2}\left({\frac {B}{2}}\right):0$

Trilinear coordinates for the Nagel point are given by

\csc ^{2}\left({\frac {A}{2}}\right):\csc ^{2}\left({\frac {B}{2}}\right):\csc ^{2}\left({\frac {C}{2}}\right)

or, equivalently, by the Law of Sines,

{\frac {b+c-a}{a}}:{\frac {c+a-b}{b}}:{\frac {a+b-c}{c}}

It is the isotomic conjugate of the Gergonne point.

Relation to area of the triangle

The radii of the incircles and excircles are closely related to the area of the triangle.^[29]

Incircle

Suppose $\triangle ABC$ has an incircle with radius r and center I. Let a be the length of BC, b the length of AC, and c the length of AB. Now, the incircle is tangent to AB at some point C′, and so $\angle AC'I$ is right. Thus the radius C'I is an altitude of $\triangle IAB$ . Therefore, $\triangle IAB$ has base length c and height r, and so has area ${\tfrac {1}{2}}cr$ . Similarly, $\triangle IAC$ has area ${\tfrac {1}{2}}br$ and $\triangle IBC$ has area ${\tfrac {1}{2}}ar$ . Since these three triangles decompose $\triangle ABC$ , we see that

\Delta ={\frac {1}{2}}(a+b+c)r=sr,

and

r={\frac {\Delta }{s}},

where $\Delta$ is the area of $\triangle ABC$ and $s={\frac {1}{2}}(a+b+c)$ is its semiperimeter.

For an alternative formula, consider $\triangle IC'A$ . This is a right-angled triangle with one side equal to r and the other side equal to $r\cot {\frac {\angle A}{2}}$ . The same is true for $\triangle IB'A$ . The large triangle is composed of 6 such triangles and the total area is:

\Delta =r^{2}\cdot (\cot {\frac {\angle A}{2}}+\cot {\frac {\angle B}{2}}+\cot {\frac {\angle C}{2}})

Excircles

The radii of the excircles are called the exradii. Let the excircle at side AB touch at side AC extended at G, and let this excircle's radius be $r_{c}$ and its center be $I_{c}$ . Then $I_{c}G$ is an altitude of $\triangle ACI_{c}$ , so $\triangle ACI_{c}$ has area ${\tfrac {1}{2}}br_{c}$ . By a similar argument, $\triangle BCI_{c}$ has area ${\tfrac {1}{2}}ar_{c}$ and $\triangle ABI_{c}$ has area ${\tfrac {1}{2}}cr_{c}$ . Thus

\Delta ={\frac {1}{2}}(a+b-c)r_{c}=(s-c)r_{c}

So, by symmetry,

\Delta =sr=(s-a)r_{a}=(s-b)r_{b}=(s-c)r_{c}

By the Law of Cosines, we have

\cos A={\frac {b^{2}+c^{2}-a^{2}}{2bc}}

Combining this with the identity $\sin ^{2}A+\cos ^{2}A=1$ , we have

\sin A={\frac {\sqrt {-a^{4}-b^{4}-c^{4}+2a^{2}b^{2}+2b^{2}c^{2}+2a^{2}c^{2}}}{2bc}}

But $\Delta ={\tfrac {1}{2}}bc\sin A$ , and so

{\begin{aligned}\Delta &={\frac {1}{4}}{\sqrt {-a^{4}-b^{4}-c^{4}+2a^{2}b^{2}+2b^{2}c^{2}+2a^{2}c^{2}}}\\&={\frac {1}{4}}{\sqrt {(a+b+c)(-a+b+c)(a-b+c)(a+b-c)}}\\&={\sqrt {s(s-a)(s-b)(s-c)}},\end{aligned}}

which is Heron's formula.

Combining this with $sr=\Delta$ , we have

r^{2}={\frac {\Delta ^{2}}{s^{2}}}={\frac {(s-a)(s-b)(s-c)}{s}}.

Similarly, $(s-a)r_{a}=\Delta$ gives

r_{a}^{2}={\frac {s(s-b)(s-c)}{s-a}}

and

r_{a}={\sqrt {\frac {s(s-b)(s-c)}{s-a}}}.

^[30]

From these formulas one can see that the excircles are always larger than the incircle and that the largest excircle is the one tangent to the longest side and the smallest excircle is tangent to the shortest side. Further, combining these formulas yields:^[31]

\Delta ={\sqrt {rr_{a}r_{b}r_{c}}}.

The ratio of the area of the incircle to the area of the triangle is less than or equal to ${\frac {\pi }{3{\sqrt {3}}}}$ , with equality holding only for equilateral triangles.^[32]

Related constructions

Nine-point circle and Feuerbach point

The nine-point circle is tangent to the incircle and excircles

In geometry, the nine-point circle is a circle that can be constructed for any given triangle. It is so named because it passes through nine significant concyclic points defined from the triangle. These nine points are:

The midpoint of each side of the triangle
The foot of each altitude
The midpoint of the line segment from each vertex of the triangle to the orthocenter (where the three altitudes meet; these line segments lie on their respective altitudes).^[33]^[34]

In 1822 Karl Feuerbach discovered that any triangle's nine-point circle is externally tangent to that triangle's three excircles and internally tangent to its incircle; this result is known as Feuerbach's theorem. He proved that:

... the circle which passes through the feet of the altitudes of a triangle is tangent to all four circles which in turn are tangent to the three sides of the triangle... (Feuerbach 1822)

The triangle center at which the incircle and the nine-point circle touch is called the Feuerbach point.

Incentral and excentral triangles

The points of intersection of the interior angle bisectors of ABC with the segments BC, CA, AB are the vertices of the incentral triangle. Trilinear coordinates for the vertices of the incentral triangle are given by

$\ ({\text{vertex opposite}}\,A)=0:1:1$
$\ ({\text{vertex opposite}}\,B)=1:0:1$
$\ ({\text{vertex opposite}}\,C)=1:1:0$

The excentral triangle of a reference triangle has vertices at the centers of the reference triangle's excircles. Its sides are on the external angle bisectors of the reference triangle (see figure at top of page). Trilinear coordinates for the vertices of the excentral triangle are given by

$({\text{vertex opposite}}\,A)=-1:1:1$
$({\text{vertex opposite}}\,B)=1:-1:1$
$({\text{vertex opposite}}\,C)=1:1:-1$

Equations for four circles

Let x : y : z be a variable point in trilinear coordinates, and let u = cos²(A/2), v = cos²(B/2), w = cos²(C/2). The four circles described above are given equivalently by either of the two given equations:^[35]^{:p. 210–215}

Incircle:

\ u^{2}x^{2}+v^{2}y^{2}+w^{2}z^{2}-2vwyz-2wuzx-2uvxy=0

\pm {\sqrt {x}}\cos {\frac {A}{2}}\pm {\sqrt {y}}\cos {\frac {B}{2}}\pm {\sqrt {z}}\cos {\frac {C}{2}}=0

A-excircle:

\ u^{2}x^{2}+v^{2}y^{2}+w^{2}z^{2}-2vwyz+2wuzx+2uvxy=0

\pm {\sqrt {-x}}\cos {\frac {A}{2}}\pm {\sqrt {y}}\cos {\frac {B}{2}}\pm {\sqrt {z}}\cos {\frac {C}{2}}=0

B-excircle:

\ u^{2}x^{2}+v^{2}y^{2}+w^{2}z^{2}+2vwyz-2wuzx+2uvxy=0

\pm {\sqrt {x}}\cos {\frac {A}{2}}\pm {\sqrt {-y}}\cos {\frac {B}{2}}\pm {\sqrt {z}}\cos {\frac {C}{2}}=0

C-excircle:

\ u^{2}x^{2}+v^{2}y^{2}+w^{2}z^{2}+2vwyz+2wuzx-2uvxy=0

\pm {\sqrt {x}}\cos {\frac {A}{2}}\pm {\sqrt {y}}\cos {\frac {B}{2}}\pm {\sqrt {-z}}\cos {\frac {C}{2}}=0

Euler's theorem

Euler's theorem states that in a triangle:

(R-r)^{2}=d^{2}+r^{2},

where R and r are the circumradius and inradius respectively, and d is the distance between the circumcenter and the incenter.

For excircles the equation is similar:

(R+r_{ex})^{2}=d_{ex}^{2}+r_{ex}^{2},

where r_ex is the radius of one of the excircles, and d_ex is the distance between the circumcenter and this excircle's center.^[36]^[37]^[38]

Generalization to other polygons

Some (but not all) quadrilaterals have an incircle. These are called tangential quadrilaterals. Among their many properties perhaps the most important is that their two pairs of opposite sides have equal sums. This is called the Pitot theorem.

More generally, a polygon with any number of sides that has an inscribed circle—one that is tangent to each side—is called a tangential polygon.

Notes

↑ Kay (1969, p. 140)
↑ Altshiller-Court (1925, p. 74)
1 2 3 4 5 Altshiller-Court (1925, p. 73)
↑ Kay (1969, p. 117)
1 2 3 Johnson, Roger A., Advanced Euclidean Geometry, Dover, 2007 (orig. 1929).
1 2 Encyclopedia of Triangle Centers Archived 2012-04-19 at the Wayback Machine., accessed 2014-10-28.
↑ Allaire, Patricia R.; Zhou, Junmin; Yao, Haishen (March 2012), "Proving a nineteenth century ellipse identity", Mathematical Gazette, 96: 161–165 .
↑ Altshiller-Court, Nathan (1980), College Geometry, Dover Publications . #84, p. 121.
↑ Chu, Thomas, The Pentagon, Spring 2005, p. 45, problem 584.
1 2 3 4 Bell, Amy, "Hansen’s right triangle theorem, its converse and a generalization", Forum Geometricorum 6, 2006, 335–342.
↑ Kodokostas, Dimitrios, "Triangle Equalizers," Mathematics Magazine 83, April 2010, pp. 141-146.
↑ Allaire, Patricia R.; Zhou, Junmin; and Yao, Haishen, "Proving a nineteenth century ellipse identity", Mathematical Gazette 96, March 2012, 161-165.
↑ Altshiller-Court, Nathan. College Geometry, Dover Publications, 1980.
↑ Mathematical Gazette, July 2003, 323-324.
↑ Posamentier, Alfred S., and Lehmann, Ingmar. The Secrets of Triangles, Prometheus Books, 2012.
1 2 3 Franzsen, William N. (2011). "The distance from the incenter to the Euler line" (PDF). Forum Geometricorum. 11: 231–236. MR 2877263. .
↑ Coxeter, H.S.M. "Introduction to Geometry 2nd ed. Wiley, 1961.
↑ Minda, D., and Phelps, S., "Triangles, ellipses, and cubic polynomials", American Mathematical Monthly 115, October 2008, 679-689: Theorem 4.1.
↑ Weisstein, Eric W. "Contact Triangle." From MathWorld--A Wolfram Web Resource. http://mathworld.wolfram.com/ContactTriangle.html
↑ Christopher J. Bradley and Geoff C. Smith, "The locations of triangle centers", Forum Geometricorum 6 (2006), 57--70. http://forumgeom.fau.edu/FG2006volume6/FG200607index.html
↑ Dekov, Deko (2009). "Computer-generated Mathematics : The Gergonne Point" (PDF). Journal of Computer-generated Euclidean Geometry. 1: 1–14.
↑ Altshiller-Court (1925, p. 74)
↑ Altshiller-Court (1925, p. 79)
↑ Altshiller-Court (1925, p. 79)
↑ Baker, Marcus, "A collection of formulae for the area of a plane triangle," Annals of Mathematics, part 1 in vol. 1(6), January 1885, 134-138. (See also part 2 in vol. 2(1), September 1885, 11-18.)
↑ Minda, D., and Phelps, S., "Triangles, ellipses, and cubic polynomials", American Mathematical Monthly 115, October 2008, 679-689: Theorem 4.1.
↑ Grinberg, Darij, and Yiu, Paul, "The Apollonius Circle as a Tucker Circle", Forum Geometricorum 2, 2002: pp. 175-182.
↑ Stevanovi´c, Milorad R., "The Apollonius circle and related triangle centers", Forum Geometricorum 3, 2003, 187-195.
↑ Coxeter, H.S.M. "Introduction to Geometry 2nd ed. Wiley, 1961.
↑ Altshiller-Court (1925, p. 79)
↑ Baker, Marcus, "A collection of formulae for the area of a plane triangle," Annals of Mathematics, part 1 in vol. 1(6), January 1885, 134-138. (See also part 2 in vol. 2(1), September 1885, 11-18.)
↑ Minda, D., and Phelps, S., "Triangles, ellipses, and cubic polynomials", American Mathematical Monthly 115, October 2008, 679-689: Theorem 4.1.
↑ Altshiller-Court (1925, pp. 103–110)
↑ Kay (1969, pp. 18,245)
↑ Whitworth, William Allen. Trilinear Coordinates and Other Methods of Modern Analytical Geometry of Two Dimensions, Forgotten Books, 2012 (orig. Deighton, Bell, and Co., 1866). http://www.forgottenbooks.com/search?q=Trilinear+coordinates&t=books
↑ Nelson, Roger, "Euler's triangle inequality via proof without words," Mathematics Magazine 81(1), February 2008, 58-61.
↑ Johnson, R. A. Modern Geometry, Houghton Mifflin, Boston, 1929: p. 187.
↑ Emelyanov, Lev, and Emelyanova, Tatiana. "Euler’s formula and Poncelet’s porism", Forum Geometricorum 1, 2001: pp. 137–140.

References

Altshiller-Court, Nathan (1925), College Geometry: An Introduction to the Modern Geometry of the Triangle and the Circle (2nd ed.), New York: Barnes & Noble, LCCN 52013504
Kay, David C. (1969), College Geometry, New York: Holt, Rinehart and Winston, LCCN 69012075
Kimberling, Clark (1998). "Triangle Centers and Central Triangles". Congressus Numerantium (129): i–xxv,1–295.
Kiss, Sándor (2006). "The Orthic-of-Intouch and Intouch-of-Orthic Triangles". Forum Geometricorum (6): 171–177.

External links

Derivation of formula for radius of incircle of a triangle
Weisstein, Eric Wolfgang. "Incircle". MathWorld.

Interactive

Triangle incenter Triangle incircle Incircle of a regular polygon With interactive animations
Constructing a triangle's incenter / incircle with compass and straightedge An interactive animated demonstration
Equal Incircles Theorem at cut-the-knot
Five Incircles Theorem at cut-the-knot
Pairs of Incircles in a Quadrilateral at cut-the-knot
An interactive Java applet for the incenter

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