Belgian general election, 1886

Belgian general election, 1886
Belgium
8 June 1886 (1886-06-08)

69 of the 138 seats in the Chamber of Representatives
70 seats needed for a majority

  First party Second party
 
Party Catholic Liberal
Last election 86 seats 52 seats
Seats won 98 40
Seat change Increase12 Decrease12

Government before election

Beernaert Government
Catholic

Elected Government

Beernaert Government
Catholic

This article is part of a series on the
politics and government of
Belgium
Constitution
Foreign relations

Partial general elections were held in Belgium on 8 June 1886.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 98 of the 138 seats.[2]

Under the alternating system, elections were only held in four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders.

The Catholics continued their gains, after the 1884 elections that gave them a victory over the Liberals. With the defeat of the Liberals by the Catholics in the eight-member arrondissement of Ghent, the Catholics now had all "Flemish" seats. Catholics also gained both seats of the arrondissement of Waremme and two out of seven in the arrondissement of Charleroi.

Results

Chamber of Representatives

Party Votes % Seats
Won Total +/–
Liberal Party18,96551.33740–12
Catholic Party17,97948.73298+12
Invalid/blank votes
Total36,944100691380
Registered voters/turnout57,962
Source: Mackie & Rose,[3] Sternberger et al

References

  1. Codebook Constituency-level Elections Archive, 2003
  2. 1 2 Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
  3. Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp50–51
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