Belgian general election, 1872
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63 of the 124 seats in the Chamber of Representatives 63 seats needed for a majority | |||||||||||||||||||
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This article is part of a series on the politics and government of Belgium |
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Partial general elections were held in Belgium on 11 June 1872.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 71 of the 124 seats.[2] Voter turnout was 55.5%, although only 54,933 people were eligible to vote.
Under the alternating system, elections were only held in five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.
Results
Chamber of Representatives
Party | Votes | % | Seats | ||
---|---|---|---|---|---|
Won | Total | +/– | |||
Catholic Party | 20,949 | 68.8 | 43 | 71 | –1 |
Liberal Party | 9,455 | 31.0 | 20 | 53 | +1 |
Others | 66 | 0.2 | 0 | 0 | New |
Invalid/blank votes | 5,709 | – | – | – | – |
Total | 36,179 | 100 | 63 | 124 | 0 |
Registered voters/turnout | 54,933 | 55.5 | – | – | – |
Source: Mackie & Rose,[3] Sternberger et al. |
The results exclude the voting figures for the Nivelles constituency.[3]
References
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