2018 Snooker Shoot-Out

Snooker Shoot-Out
Tournament information
Dates 8–11 February 2018
City Watford
Country England
Organisation(s) WPBSA
Format Ranking event
Total prize fund £
Winner's share £32,000
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The 2018 Snooker Shoot-Out is a professional ranking snooker tournament that will take place from 8-11 February 2018 in Watford, England.[1] It will be played under a variation of the standard rules of snooker, and will be the thirteenth ranking event of the 2017/2018 season.

Anthony McGill is the defending champion, having beaten Xiao Guodong 67–19 in the 2017 final.

Prize fund

The breakdown of prize money for this year is shown below:[2]

  • Winner: £32,000
  • Runner-up: £16,000
  • Semi-final: £8,000
  • Quarter-final: £4,000
  • Last 16: £2,000
  • Last 32: £1,000
  • Last 64: £500
  • Last 128: £250 (prize money at this stage will not count towards prize money rankings)
  • Non-televised highest break: £TBC
  • Televised highest break: £TBC
  • Total: £

The "rolling 147 prize" for a maximum break stands at £

References

  1. ↑ "2017/18 World Snooker Calendar" (PDF). World Professional Billiards and Snooker Association. 14 July 2017. Retrieved 14 July 2017.
  2. ↑ "Indicative Prize Money Rankings Schedule 2017/2018 Season" (PDF). worldsnooker.com. World Professional Billiards and Snooker Association. 14 July 2017. Retrieved 14 July 2017.
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