2007 ASB Classic – Singles

Singles
2007 ASB Classic
Champion	Jelena Janković
Runner-up	Vera Zvonareva
Final score	7–6(11–9), 5–7, 6–3

Marion Bartoli was the defending champion, but lost in the second round against Émilie Loit.

Jelena Janković won the title, beating Vera Zvonareva 7–6^(11–9), 5–7, 6–3 in the final.

Draw

Seeds

Key

Finals

	Semifinals							Final
	1	Jelena Janković	3
		Camille Pin	0r
								1	Jelena Janković	7	5	6
								5	Vera Zvonareva	69	7	3
	5	Vera Zvonareva	6	7
		Jill Craybas	3	5

Top Half

	First Round							Second Round							Quarterfinals							Semifinals
	1	J Janković	6	6
		J Schruff	3	4				1	J Janković	6	6
	LL	M Johansson	64	1					E Laine	2	1
		E Laine	7	6											1	J Janković	6	6
	WC	M Erakovic	6	4	7										7	E Daniilidou	3	4
	Q	M Tu	3	6	5			WC	M Erakovic	4	6	4
		J Kostanić	3	6	1			7	E Daniilidou	6	4	6
	7	E Daniilidou	6	4	6																	1	J Janković	3
	4	M Bartoli	7	6																			C Pin	0r
		A Morita	64	3				4	M Bartoli	5	4
		E Birnerová	1	1					É Loit	7	6
		É Loit	6	6												É Loit	3	3
	Q	Y Meusburger	7	6												C Pin	6	6
		E Bychkova	5	0				Q	Y Meusburger	6	3	3
		C Pin	6	5	6				C Pin	2	6	6
	8	S Perry	3	7	2

Bottom Half

	First Round							Second Round							Quarterfinals							Semifinals
	5	V Zvonareva	5	6	6
	Q	L Osterloh	7	2	3			5	V Zvonareva	6	6
		R Oprandi	3	4					L Granville	3	4
		L Granville	6	6											5	V Zvonareva	7	2
	Q	V Razzano	7	6											Q	V Razzano	5	0r
		K Kanepi	61	1				Q	V Razzano	6	7
		D Cibulková	1	6	2			3	D Hantuchová	1	5
	3	D Hantuchová	6	3	6																	5	V Zvonareva	6	7
	6	M Müller	6	1	1																		J Craybas	3	5
		P Suárez	3	6	6				P Suárez	7	6
	WC	L Baker	1	1					T Sun	5	4
		T Sun	6	6												P Suárez	3	64
		J Craybas	7	6												J Craybas	6	7
		A Nakamura	5	2					J Craybas	6	7
		G Dulko	6	64	6				G Dulko	3	5
	2	A Myskina	1	7	2

^[1]

References