1967 CONCACAF Championship qualification

For the 1967 CONCACAF Championship, a total of 10 teams entered the competition.  Honduras, as the hosts, and  Mexico, as the defending champions, qualified automatically, leaving 4 spots open for competition. The 8 teams were divided into 2 groups in which the top 2 in each group advanced to the final tournament.

Group 1

Played in Kingston, Jamaica.

The group was also referred to as the Red Stripe Trophy within Jamaica. The group was sponsored by Desnoes & Geddes, the brewery of Red Stripe beer.[1]

Rank Team Pts Pld W D L GF GA GD
1  Haiti 7431073+4
2  Trinidad and Tobago 54211770
3  Jamaica 44121440
4  Cuba 2402257-2
5  Netherlands Antilles 2402246-2

12 January 1967
Cuba  1–1  Haiti

14 January 1967
Jamaica  2–1  Cuba

16 January 1967
Haiti  4–2  Trinidad and Tobago

17 January 1967
Netherlands Antilles  2–2  Cuba
Dirks
Perez 		Hernandez
Mico

19 January 1967
Haiti  1–0  Netherlands Antilles

20 January 1967
Trinidad and Tobago  2–1  Cuba

21 January 1967
Jamaica  0–1  Haiti

Haiti and Trinidad and Tobago qualified for the final tournament.

Group 2

Played in Ciudad de Guatemala, Guatemala.

Rank Team Pts Pld W D L GF GA GD
1  Guatemala 4220062+4
2  Nicaragua 22101440
3  Panama 0200226-4

13 February 1967
Guatemala  3–1  Panama

15 February 1967
Guatemala  3–1  Nicaragua

17 February 1967
Panama  1–3  Nicaragua

Guatemala and Nicaragua qualified for the final tournament.

References

  1. ↑ "Haitian goalkeeper suspended". Kingston Gleaner. 23 January 1967. p. 28.

See also

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