United States presidential election in Missouri, 1844
Main article: United States presidential election, 1844
| Elections in Missouri | ||||||||||||||||
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The 1844 United States presidential election in Missouri took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Missouri by a margin of 13.96%.
Results
| United States presidential election in Missouri, 1844[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 41,322 | 56.98% | 7 | 100.00% | ||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 31,200 | 43.02% | 0 | 0.00% | ||
| Total | 72,522 | 100.00% | 7 | 100.00% | ||||
References
- ↑ "1844 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved 23 December 2013.
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