United States presidential election in Delaware, 1836

United States presidential election in Delaware, 1836
Delaware
November 3 – December 7, 1836
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote 3 0
Popular vote 4,736 4,154
Percentage 53.24% 46.70%
Elections in Delaware

The 1836 United States presidential election in Delaware took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Delaware by a margin of 6.54%.

Results

United States presidential election in Delaware, 1836[1]
Party Candidate Votes Percentage Electoral votes
Whig William Henry Harrison 4,736 53.24% 3
Democratic Martin Van Buren 4,154 46.70% 0
N/A Other 5 0.06% 0
Totals 8,895 100.0% 3

References

  1. ↑ "1836 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 4 August 2012.
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