United States presidential election in Connecticut, 1836

United States presidential election in Connecticut, 1836
Connecticut
November 3 – December 7, 1836
 
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Johnson Francis Granger
Electoral vote 8 0
Popular vote 19,294 18,799
Percentage 50.65% 49.35%

The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a margin of 1.3%.

Results

United States presidential election in Connecticut, 1836[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 19,294 50.65% 8
Whig William Henry Harrison 18,799 49.35% 0
Totals 38,093 100.0% 8

References

  1. ↑ "1836 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 4 August 2012.
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