United States elections, 1988
The 1988 United States general election was held on November 8, and elected the members of the 101st United States Congress. The Republican Party retained the presidency, while the Democratic Party retained control of Congress.
Republican Vice President George H. W. Bush was elected to serve as the 41st President of the United States, defeating Democratic Governor Michael Dukakis of Massachusetts.[1] Bush won the popular vote by just under eight points, and won 426 of the 538 electoral votes. Bush won the Republican nomination over Kansas Senator Bob Dole and televangelist Pat Robertson of Virginia. Dukakis won the Democratic nomination over Reverend Jesse Jackson of Illinois, Tennessee Senator Al Gore, and Missouri Congressman Dick Gephardt. This was the first time since the Great Depression that the Republican Party won three presidential elections in a row, and Bush was the first sitting vice president to win a presidential election since Martin Van Buren in 1836.
Neither the Senate nor the House saw any significant partisan change, and the Democratic Party retained control of both chambers. In the gubernatorial elections, the Democratic Party picked up one governorship.
See also
References
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- See also
- Presidential elections
- Senate elections
- House elections
- Gubernatorial elections
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