San Cipriano Po
| San Cipriano Po | |
|---|---|
| Comune | |
| Comune di San Cipriano Po | |
  San Cipriano Po Location of San Cipriano Po in Italy | |
| Coordinates: 45°6′N 9°15′E / 45.100°N 9.250°ECoordinates: 45°6′N 9°15′E / 45.100°N 9.250°E | |
| Country | Italy |
| Region | Lombardy |
| Province | Province of Pavia (PV) |
| Area | |
| • Total | 8.7 km2 (3.4 sq mi) |
| Population (Dec. 2004) | |
| • Total | 435 |
| • Density | 50/km2 (130/sq mi) |
| Time zone | CET (UTC+1) |
| • Summer (DST) | CEST (UTC+2) |
| Postal code | 27043 |
| Dialing code | 0385 |
San Cipriano Po is a comune (municipality) in the Province of Pavia in the Italian region Lombardy, located about 40 km south of Milan and about 12 km southeast of Pavia. As of 31 December 2004, it had a population of 435 and an area of 8.7 km².[1]
San Cipriano Po borders the following municipalities: Albaredo Arnaboldi, Belgioioso, Broni, Spessa, Stradella.
Demographic evolution
References
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