Pickaway Township, Shelby County, Illinois
Pickaway Township | |
Township | |
Country | United States |
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State | Illinois |
County | Shelby |
Elevation | 718 ft (218.8 m) |
Coordinates | 39°33′47″N 88°52′09″W / 39.56306°N 88.86917°WCoordinates: 39°33′47″N 88°52′09″W / 39.56306°N 88.86917°W |
Area | 29.7 sq mi (76.9 km2) |
- land | 29.7 sq mi (77 km2) |
- water | 0 sq mi (0 km2) |
Population | 179 (2010) |
Density | 6 / sq mi (2.3 / km2) |
Organized | November 8, 1859 |
Timezone | CST (UTC-6) |
- summer (DST) | CDT (UTC-5) |
ZIP code | XXXXX |
Area code | 217 |
Location in Shelby County
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Location of Pickaway Township in Illinois
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Location of Illinois in the United States
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Pickaway Township is located in Shelby County, Illinois. As of the 2010 census, its population was 179 and it contained 74 housing units.[1]
Geography
According to the 2010 census, the township has a total area of 29.7 square miles (77 km2), all land.[1]
References
- 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-28.
External links
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