Fern Prairie, Washington
Fern Prairie, Washington | |
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Census-designated place | |
Fern Prairie Location of Fern Prairie, Washington | |
Coordinates: 45°38′11″N 122°23′55″W / 45.63639°N 122.39861°WCoordinates: 45°38′11″N 122°23′55″W / 45.63639°N 122.39861°W | |
Country | United States |
State | Washington |
County | Clark |
Area | |
• Total | 5.0 sq mi (13.0 km2) |
• Land | 5.0 sq mi (13.0 km2) |
• Water | 0.0 sq mi (0.0 km2) |
Elevation | 459 ft (140 m) |
Population (2010) | |
• Total | 1,884 |
• Density | 376/sq mi (145.0/km2) |
Time zone | Pacific (PST) (UTC-8) |
• Summer (DST) | PDT (UTC-7) |
FIPS code | 53-23690 |
GNIS feature ID | 1519499 |
Fern Prairie is a census-designated place (CDP) in Clark County, Washington, United States. The population was 1,884 at the 2010 census.[1]
It is located in southern Clark County, 16 miles (26 km) east of downtown Vancouver and 4 miles (6 km) north of Camas.
References
- ↑ "Geographic Identifiers: 2010 Demographic Profile Data (G001): Fern Prairie CDP, Washington". U.S. Census Bureau, American Factfinder. Retrieved August 31, 2015.
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