Bockstein spectral sequence

In mathematics, the Bockstein spectral sequence is a spectral sequence relating the homology with mod p coefficients and the homology reduced mod p. It is named after Meyer Bockstein.

Definition

Let C be a chain complex of torsion-free abelian groups and p a prime number. Then we have the exact sequence:

0 \to C \overset{p}\to C \overset{\text{mod } p}\to C \otimes \mathbb{Z}/p \to 0.

Taking integral homology H, we get the exact couple of "doubly graded" abelian groups:

H_*(C) \overset{i = p}\to H_*(C) \overset{j} \to H_*(C \otimes \mathbb{Z}/p) \overset{k} \to .

where the grading goes: H_*(C)_{s, t} = H_{s+t}(C) and the same for H_*(C \otimes \mathbb{Z}/p), \operatorname{deg} i = (1, -1), \operatorname{deg} j = (0, 0), \operatorname{deg} k = (-1, 0).

This gives the first page of the spectral sequence: we take E_{s, t}^1 = H_{s+t}(C \otimes \mathbb{Z}/p) with the differential {}^1 d = j \circ k. The derived couple of the above exact couple then gives the second page and so forth. Explicitly, we have D^r = p^{r-1}  H_*(C) that fits into the exact couple:

D^r \overset{i=p}\to D^r \overset{{}^r j} \to E^r \overset{k}\to  

where {}^r j is (\text{mod } p) \circ p^{-{r+1}} and \operatorname{deg} {}^r j = (-(r-1), r - 1) (the degrees of i, k are the same as before). Now, taking D_n^r \otimes - of 0 \to \mathbb{Z} \overset{p}\to \mathbb{Z} \to \mathbb{Z}/p \to 0, we get:

0 \to \operatorname{Tor}_1^{\mathbb{Z}}(D_n^r, \mathbb{Z}/p) \to D_n^r \overset{p}\to D_n^r \to D_n^r \otimes \mathbb{Z}/p \to 0.

This tells the kernel and cokernel of D^r_n \overset{p}\to D^r_n. Expanding the exact couple into a long exact sequence, we get: for any r,

0 \to (p^{r-1} H_n(C)) \otimes \mathbb{Z}/p \to E^r_{n, 0} \to \operatorname{Tor}(p^{r-1} H_{n-1}(C), \mathbb{Z}/p) \to 0.

When r = 1, this is the same thing as the universal coefficient theorem for homology.

Assume the abelian group H_*(C) is finitely generated; in particular, only finitely many cyclic modules of the form \mathbb{Z}/p^s can appear as a direct summand of H_*(C). Letting r \to \infty we thus see E^\infty is isomorphic to (\text{free part of } H_*(C)) \otimes \mathbb{Z}/p.

References


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