2014 ATP Shenzhen Open – Doubles

Doubles
2014 ATP Shenzhen Open
Champions Netherlands Jean-Julien Rojer
Romania Horia Tecău
Runners-up Australia Sam Groth
Australia Chris Guccione
Final score 6–4, 7–6(7–4)

This was the first edition of the tournament.

Jean-Julien Rojer and Horia Tecău won the title, defeating Sam Groth and Chris Guccione in the final, 6–4, 7–6(7–4).

Seeds

Draw

Key

Draw

First Round   Quarterfinals   Semifinals   Final
1  Netherlands J-J Rojer
 Romania H Tecău		 6 6  
 United Kingdom C Fleming
 Sweden R Lindstedt		 2 1     1  Netherlands J-J Rojer
 Romania H Tecău		 6 5 [10]  
 Russia E Donskoy
 Russia T Gabashvili		 6 6      Russia E Donskoy
 Russia T Gabashvili		 4 7 [7]  
WC  China Z Qiu
 China R Te		 3 3       1  Netherlands J-J Rojer
 Romania H Tecău		 3 6 [10]  
3  India R Bopanna
 Pakistan A-u-H Qureshi		 6 4 [10]        Colombia S Giraldo
 New Zealand M Venus		 6 1 [5]  
 Australia M Ebden
 Italy A Seppi		 4 6 [7]     3  India R Bopanna
 Pakistan A-u-H Qureshi		 4 64
 Argentina M González
 Argentina J Mónaco		 6 3 [4]      Colombia S Giraldo
 New Zealand M Venus		 6 77  
 Colombia S Giraldo
 New Zealand M Venus		 4 6 [10]       1  Netherlands J-J Rojer
 Romania H Tecău		 6 77
 Australia S Groth
 Australia C Guccione		 6 6        Australia S Groth
 Australia C Guccione		 4 64
WC  China B Ouyang
 China A Wang		 3 4      Australia S Groth
 Australia C Guccione		 67 77 [10]  
 United Kingdom J Delgado
 Luxembourg G Müller		 3 64     4  Poland M Fyrstenberg
 Belarus M Mirnyi		 79 64 [4]  
4  Poland M Fyrstenberg
 Belarus M Mirnyi		 6 77        Australia S Groth
 Australia C Guccione		 77 6
 Sweden J Brunström
 United States N Monroe		 63 6 [10]       2  Colombia JS Cabal
 Colombia R Farah		 65 4  
 Belarus S Betov
 Belarus A Bury		 77 3 [5]      Sweden J Brunström
 United States N Monroe		 6 4 [5]
Alt  Switzerland M Chiudinelli
 Slovakia L Lacko		 1 1     2  Colombia JS Cabal
 Colombia R Farah		 4 6 [10]  
2  Colombia JS Cabal
 Colombia R Farah		 6 6  

References

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