1968 Dutch Open (tennis)

1968 Dutch Open
Date 22 – 28 July
Edition 12th
Draw 32S / 16D
Surface Clay / Outdoor
Location Hilversum, Netherlands
Venue 't Melkhuisje
Champions
Men's Singles
South Africa Bob Maud
Women's Singles
Australia Margaret Court
Men's Doubles
Czechoslovakia Jan Kodeš / Czechoslovakia Jan Kukal
Women's Doubles
South Africa Annette Du Plooy / South Africa Pat Walkden
Mixed Doubles
South Africa Annette Du Plooy / South Africa Bob Maud

The 1968 Dutch Open was a combined men's and women's tennis tournament staged in Hilversum, Netherlands. The tournament was played on outdoor clay courts and was held from 22 July to 28 July 1968. It was the 12th edition of the tournament and the first in the Open era of tennis. Bob Maud and Margaret Smith won the singles titles.[1][2]

Winners

Men's Singles

South Africa Bob Maud defeated Hungary István Gulyás 7–9, 7–5, 6–0, 1–6, 13–11

Women's Singles

Australia Margaret Court defeated Australia Judy Tegart 8–6, 6–0

Men's Doubles

Czechoslovakia Jan Kodeš / Czechoslovakia Jan Kukal defeated West Germany Ingo Buding / West Germany Harald Elschenbroich 6–3, 6–1

Women's Doubles

South Africa Annette Du Plooy / South Africa Pat Walkden defeated Australia Judy Tegart / Netherlands Astrid Suurbeek 6–2, 3–6, 6–3

Mixed Doubles

South Africa Annette Du Plooy / South Africa Bob Maud defeated Australia Margaret Court / Netherlands Tom Okker two sets

References

  1. ↑ John Barrett, ed. (1969). BP Yearbook of World Tennis. London: Ward Lock. p. 167. ISBN 978-0706318241. OCLC 502175694.
  2. ↑ "Maud onverwacht winnaar". De Telegraaf (in Dutch) (Delpher). 29 July 1968.

External links

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