United States presidential election in Wisconsin, 1996

United States presidential election in Wisconsin, 1996
Wisconsin
November 5, 1996
 
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Patrick Choate
Electoral vote 11 0 0
Popular vote 1,071,971 845,029 227,339
Percentage 48.81% 38.48% 10.35%

County Results
  Clinton—80-90%
  Clinton—60-70%
  Clinton—50-60%
  Dole—40-50%
  Dole—50-60%
President before election

Bill Clinton
Democratic

 Elected President

Bill Clinton
Democratic

Elections in Wisconsin

The 1996 United States presidential election in Wisconsin took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

Wisconsin was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 48.81% to 38.48% by a margin of 10.33%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 10.35% of the popular vote.[1]

Results

United States presidential election in Wisconsin, 1996
Party Candidate Running mate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) Al Gore 1,071,971 48.81% 11
Republican Bob Dole Jack Kemp 845,029 38.48% 0
Reform Ross Perot Patrick Choate 227,339 10.35% 0
Independent Ralph Nader Winona LaDuke 28,723 1.31% 0
U.S. Taxpayers' Party Howard Phillips Herbert Titus 8,811 0.40% 0
Libertarian Harry Browne Jo Jorgensen 7,929 0.36% 0
No party Write-in 2,324 0.11% 0
Independent Dr. John Hagelin Dr. V. Tompkins 1,379 0.06% 0
Independent Monica Moorehead Gloria La Riva 1,333 0.06% 0
Independent Mary Cal Hollis Eric Chester 848 0.04% 0
Independent James Harris Laura Garza 483 0.02% 0

References

  1. ↑ Dave Leip's Atlas of United States Presidential Election Results - 1996 Wisconsin Results

See also