United States presidential election in Vermont, 1840

The 1840 United States presidential election in Vermont took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 28.43%.

Results

United States presidential election in Vermont, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 32,445 63.90% 7 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 18,009 35.47% 0 0.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 319 0.63% 0 0.00%
Total 50,773 100.00% 7 100.00%

References

  1. ↑ "1840 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved 23 December 2013.