United States presidential election in Oregon, 1996
The 1996 United States presidential election in Oregon took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
Oregon was won by President Bill Clinton (D) over Senator Bob Dole (R-Kansas), with Clinton winning 47.2% to 39.1% by a margin of 8.1%. Billionaire businessman Ross Perot (Reform-Texas) finished in third with 8.8% of the popular vote.[1]
Oregon was one of thirteen states where on the election ballot, James Campbell of California, Perot's former boss at IBM, was listed as a stand-in Vice-Presidential candidate.[2]
Results
United States presidential election in Oregon, 1996[1] |
Party |
Candidate |
Votes |
Percentage |
Electoral votes |
|
Democratic |
Bill Clinton |
649,641 |
47.15% |
7 |
|
Republican |
Bob Dole |
538,152 |
39.06% |
0 |
|
Reform |
Ross Perot |
121,221 |
8.80% |
0 |
|
Pacific Green |
Ralph Nader |
49,415 |
3.59% |
0 |
|
Libertarian |
Harry Browne |
8,093 |
0.65% |
0 |
|
Independent |
Howard Phillips |
3,379 |
0.25% |
0 |
|
Natural Law |
John Hagelin |
2,798 |
0.20% |
0 |
|
Write-ins |
|
2,329 |
0.17% |
0 |
|
Socialist |
Mary Cal Hollis |
1,922 |
0.14% |
0 |
Totals |
1,462,643 |
100.0% |
7 |
References
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