United States presidential election in Alabama, 1840

The 1840 United States presidential election in Alabama took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Alabama by a margin of 8.76%.

Results

United States presidential election in Alabama, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 33,996 54.38% 7 100.00%
Whig William Henry Harrison of Ohio John Tyler of Virginia 28,515 45.62% 0 0.00%
Total 62,511 100.00% 7 100.00%

References

  1. ↑ "1840 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved 23 December 2013.