Sherman Township, Hardin County, Iowa

Sherman Township
Township
Coordinates: 42°20′23″N 093°24′17″W / 42.33972°N 93.40472°WCoordinates: 42°20′23″N 093°24′17″W / 42.33972°N 93.40472°W
Country  United States
State  Iowa
County Hardin
Area
 • Total 35.98 sq mi (93.19 km2)
 • Land 35.98 sq mi (93.19 km2)
 • Water (0%) 0 sq mi ((0%) 0 km2)
Elevation[1] 1,142 ft (348 m)
Population (2000)
 • Total 461
 • Density 13.2/sq mi (5.1/km2)
FIPS code 468 697[2][3]
GNIS feature ID 0468696

Sherman Township is a township located in Hardin County, Iowa. As of the 2010 Census, its population was 738.[4][1]

History

Sherman Township was founded in 1870.[5] It is named for William Tecumseh Sherman.[6]

References

  1. ↑ 1.0 1.1 "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
  3. ↑ U.S. Geological Survey Geographic Names Information System: Sherman Township, Hardin County, Iowa
  4. ↑ "Find a County". National Association of Counties. Retrieved 2011-06-07.
  5. ↑ Moir, William J. (1911). Past and Present of Hardin County, Iowa. Unigraphic. p. 319.
  6. ↑ History of Hardin County, Iowa. Union Publishing Company. 1883. p. 904.