Shelby Township, Ripley County, Indiana

Shelby Township
Township
Coordinates: 38°58′19″N 85°22′34″W / 38.97194°N 85.37611°WCoordinates: 38°58′19″N 85°22′34″W / 38.97194°N 85.37611°W
Country United States
State Indiana
County Ripley
Government
  Type Indiana township
Area
  Total 69.39 sq mi (179.7 km2)
  Land 69.11 sq mi (179.0 km2)
  Water 0.27 sq mi (0.7 km2)
Elevation[1] 912 ft (278 m)
Population (2010)
  Total 999
  Density 14.5/sq mi (5.6/km2)
FIPS code 18-69264[2]
GNIS feature ID 453845

Shelby Township is one of eleven townships in Ripley County, Indiana. As of the 2010 census, its population was 999 and it contained 387 housing units.[3]

Geography

According to the 2010 census, the township has a total area of 69.39 square miles (179.7 km2), of which 69.11 square miles (179.0 km2) (or 99.60%) is land and 0.27 square miles (0.70 km2) (or 0.39%) is water.[3]

References

  1. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
  3. 3.0 3.1 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.

External links