San Francisco Chapulapa
| San Francisco Chapulapa | |
|---|---|
| Municipality and town | |
  San Francisco Chapulapa Location in Mexico | |
| Coordinates: 17°56′N 96°45′W / 17.933°N 96.750°WCoordinates: 17°56′N 96°45′W / 17.933°N 96.750°W | |
| Country |
 Mexico |
| State | Oaxaca |
| Area | |
| • Total | 19.14 km2 (7.39 sq mi) |
| Population (2005) | |
| • Total | 1,968 |
| Time zone | Central Standard Time (UTC-6) |
| • Summer (DST) | Central Daylight Time (UTC-5) |
San Francisco Chapulapa is a town and municipality in Oaxaca in south-western Mexico. The municipality covers an area of 19.14 km2 (7 sq mi). It is part of Cuicatlán District in the north of the Cañada Region.
As of 2005, the municipality had a total population of 1968.[1]
References
- ↑ "San Francisco Chapulapa". Enciclopedia de los Municipios de México. Instituto Nacional para el Federalismo y el Desarrollo Municipal. Retrieved June 12, 2009.