Sękowice, Lubusz Voivodeship
See also: Sękowice, Opole Voivodeship
| Sękowice | |
|---|---|
| Village | |
  Sękowice | |
| Coordinates: 51°55′N 14°43′E / 51.917°N 14.717°E | |
| Country |
 Poland |
| Voivodeship | Lubusz |
| County | Krosno Odrzańskie |
| Gmina | Gmina Gubin |
Sękowice [sɛnkɔˈvit͡sɛ] is a village in the administrative district of Gmina Gubin, within Krosno Odrzańskie County, Lubusz Voivodeship, in western Poland, close to the German border.[1] It lies approximately 4 kilometres (2 mi) south of Gubin, 30 km (19 mi) south-west of Krosno Odrzańskie, and 55 km (34 mi) west of Zielona Góra.
Before 1945 the area was part of Germany (see Territorial changes of Poland after World War II).
References
Coordinates: 51°55′00″N 14°43′00″E / 51.9167°N 14.7167°E