Sędzin
| Sędzin | |
|---|---|
| Village | |
  Sędzin | |
| Coordinates: 52°44′N 18°34′E / 52.733°N 18.567°E | |
| Country |
 Poland |
| Voivodeship | Kuyavian-Pomeranian |
| County | Aleksandrów |
| Gmina | Zakrzewo |
| Population (approx.) | 600 |
Sędzin [ˈsɛnd͡ʑin] is a village in the administrative district of Gmina Zakrzewo, within Aleksandrów County, Kuyavian-Pomeranian Voivodeship, in north-central Poland.[1] It lies 18 kilometres (11 mi) south-west of Aleksandrów Kujawski and 34 km (21 mi) south of Toruń.
The village has an approximate population of 600.
References
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Coordinates: 52°44′N 18°34′E / 52.733°N 18.567°E