Rosefield Township, Peoria County, Illinois
| Rosefield Township | |
|---|---|
| Township | |
 Location in Peoria County | |
 Peoria County's location in Illinois | |
| Country | United States |
| State | Illinois |
| County | Peoria |
| Established | November 6, 1849 |
| Area | |
| • Total | 36.53 sq mi (94.6 km2) |
| • Land | 36.38 sq mi (94.2 km2) |
| • Water | 0.15 sq mi (0.4 km2) 0.41% |
| Population (2010) | |
| • Total | 1,217 |
| • Density | 33.5/sq mi (12.9/km2) |
| Time zone | CST (UTC-6) |
| • Summer (DST) | CDT (UTC-5) |
Rosefield Township is located in Peoria County, Illinois. At the 2010 census, its population was 1,217 and it contained 489 housing units.[1]
Geography
According to the 2010 census, the township has a total area of 36.53 square miles (94.6 km2), of which 36.38 square miles (94.2 km2) (or 99.59%) is land and 0.15 square miles (0.39 km2) (or 0.41%) is water.[1]
References
- ↑ 1.0 1.1 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 28 May 2013.
External links
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Coordinates: 40°44′58″N 89°49′04″W / 40.74944°N 89.81778°W