Noble Township, Shelby County, Indiana

Noble Township
Township
Coordinates: 39°23′25″N 85°40′44″W / 39.39028°N 85.67889°WCoordinates: 39°23′25″N 85°40′44″W / 39.39028°N 85.67889°W
Country United States
State Indiana
County Shelby
Government
 • Type Indiana township
Area
 • Total 36.32 sq mi (94.1 km2)
 • Land 36.29 sq mi (94.0 km2)
 • Water 0.03 sq mi (0.08 km2)
Elevation[1] 820 ft (250 m)
Population (2010)
 • Total 1,486
 • Density 40.9/sq mi (15.8/km2)
FIPS code 18-54144[2]
GNIS feature ID 453674

Noble Township is one of fourteen townships in Shelby County, Indiana. As of the 2010 census, its population was 1,486 and it contained 668 housing units.[3]

Geography

According to the 2010 census, the township has a total area of 36.32 square miles (94.1 km2), of which 36.29 square miles (94.0 km2) (or 99.92%) is land and 0.03 square miles (0.078 km2) (or 0.08%) is water.[3]

References

  1. ↑ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
  3. ↑ 3.0 3.1 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.

External links