Hornellsville, New York

Hornellsville, New York
Town
Hornellsville, New York

Location within the state of New York

Coordinates: 42°21′N 77°40′W / 42.350°N 77.667°WCoordinates: 42°21′N 77°40′W / 42.350°N 77.667°W
Country United States
State New York
County Steuben
Area
 • Total 43.6 sq mi (113.0 km2)
 • Land 43.5 sq mi (112.6 km2)
 • Water 0.2 sq mi (0.5 km2)
Elevation 1,198 ft (365 m)
Population (2010)
 • Total 4,151
 • Density 95/sq mi (37/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 36-35683
GNIS feature ID 0979079

Hornellsville is a town in Steuben County, New York, United States. United States. The population was 4,151 at the 2000 census. The name is taken from a prominent pioneer family.[1]

The Town of Hornellsville is at the west border of the county, and contains within it Hornell, New York.

History

The town was first settled around 1790 in the vicinity of the City of Hornell. The Town of Hornellsville was formed from part of the Town of Canisteo in 1820. Territory from Hornellsville was used to form the Towns of Hartsville (1844) and part of Fremont (1854).

In 1852, the community of Hornellsville set itself apart as an incorporated village and became a city (Hornell) in 1888.

Geography

According to the United States Census Bureau, the town has a total area of 43.7 square miles (113 km2), of which, 43.5 square miles (113 km2) of it is land and 0.2 square miles (0.52 km2) of it (0.41%) is water.

The Southern Tier Expressway (Interstate 86 and New York State Route 17) passes through the north part of the town. New York State Route 21 and New York State Route 36 intersect by Hornell.

The Canisteo River flows southward through the town.

The west town line is the border of Allegany County, New York.

Demographics

As of the census[2] of 2000, there were 4,042 people, 1,669 households, and 1,098 families residing in the town. The population density was 93.0 people per square mile (35.9/km²). There were 1,830 housing units at an average density of 42.1 per square mile (16.3/km²). The racial makeup of the town was 97.92% White, 0.52% African American, 0.05% Native American, 0.82% Asian, 0.25% from other races, and 0.45% from two or more races. Hispanic or Latino of any race were 0.77% of the population.

There were 1,669 households out of which 26.7% had children under the age of 18 living with them, 53.6% were married couples living together, 8.1% had a female householder with no husband present, and 34.2% were non-families. 29.5% of all households were made up of individuals and 15.8% had someone living alone who was 65 years of age or older. The average household size was 2.34 and the average family size was 2.91.

In the town the population was spread out with 22.2% under the age of 18, 5.5% from 18 to 24, 22.6% from 25 to 44, 26.8% from 45 to 64, and 22.8% who were 65 years of age or older. The median age was 45 years. For every 100 females there were 88.9 males. For every 100 females age 18 and over, there were 86.1 males.

The median income for a household in the town was $36,932, and the median income for a family was $48,688. Males had a median income of $33,426 versus $22,193 for females. The per capita income for the town was $20,803. About 4.2% of families and 8.4% of the population were below the poverty line, including 8.7% of those under age 18 and 3.6% of those age 65 or over.

Communities and locations in Hornellsville

References

  1. ↑ Gannett, Henry (1905). The Origin of Certain Place Names in the United States. Govt. Print. Off. p. 161.
  2. ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.

External links