Harlan Township, Fayette County, Iowa

Harlan Township
Township

Location in Fayette County
Coordinates: 42°46′51″N 91°54′45″W / 42.78083°N 91.91250°WCoordinates: 42°46′51″N 91°54′45″W / 42.78083°N 91.91250°W
Country  United States
State  Iowa
County Fayette
Area
 • Total 36.79 sq mi (95.28 km2)
 • Land 36.76 sq mi (95.22 km2)
 • Water 0.03 sq mi (0.07 km2)  0.07%
Elevation 1,145 ft (349 m)
Population (2010)
 • Total 871
 • Density 24/sq mi (9.1/km2)
Time zone CST (UTC-6)
 • Summer (DST) CDT (UTC-5)
ZIP codes 50655, 50662, 50681, 52142, 52164
GNIS feature ID 0468005

Harlan Township is one of twenty townships in Fayette County, Iowa, USA. As of the 2010 census, its population was 871.[1]

Geography

According to the United States Census Bureau, Harlan Township covers an area of 36.79 square miles (95.28 square kilometers); of this, 36.76 square miles (95.22 square kilometers, 99.94 percent) is land and 0.03 square miles (0.07 square kilometers, 0.07 percent) is water.

Cities, towns, villages

Adjacent townships

Cemeteries

The township contains these two cemeteries: Hope and Long Grove.

Major highways

Landmarks

School districts

Political districts

References

  1. ↑ "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Harlan township, Fayette County, Iowa". U.S. Census Bureau, American Factfinder. Retrieved March 5, 2012.

External links