Bucktown, Indiana
| Bucktown | |
|---|---|
| Unincorporated community | |
 Sullivan County's location in Indiana | |
  Bucktown Location in Sullivan County, Indiana | |
| Coordinates: 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°WCoordinates: 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W | |
| Country | United States |
| State | Indiana |
| County | Sullivan |
| Township | Jefferson |
| Elevation | 594 ft (181 m) |
| GNIS feature ID | 431756[1] |
Bucktown is an unincorporated community in Jefferson Township, Sullivan County, Indiana. It is part of the Terre Haute Metropolitan Statistical Area.
Geography
Bucktown is located at 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W.
References
- ↑ "Bucktown, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved 2010-08-18.
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