Belgian general election, 1890

Belgian general election, 1890
Belgium
10 June 1890

All 138 seats in the Chamber of Representatives
70 seats needed for a majority
  First party Second party
 
Party Catholic Liberal
Last election 98 seats 40 seats
Seats won 94 44
Seat change Decrease4 Increase4
This article is part of a series on the
politics and government of
Belgium
Constitution
Foreign relations

Politics portal

General elections were held in Belgium on 10 June 1890.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2] Voter turnout was 73.0%, although only 59,452 people were eligible to vote.[2]

Results

Chamber of Representatives

Party Votes % Seats +/–
Catholic Party 94–4
Liberal Party 44+4
Total 1380
Sternberger et al.

References

  1. Codebook Constituency-level Elections Archive, 2003
  2. 2.0 2.1 2.2 Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105