Albany Township, Harlan County, Nebraska
Albany Township | |
---|---|
Township | |
Location in Harlan County | |
Coordinates: 40°18′36″N 099°28′02″W / 40.31000°N 99.46722°WCoordinates: 40°18′36″N 099°28′02″W / 40.31000°N 99.46722°W | |
Country | United States |
State | Nebraska |
County | Harlan |
Area | |
• Total | 35.63 sq mi (92.29 km2) |
• Land | 35.63 sq mi (92.29 km2) |
• Water | 0 sq mi (0 km2) 0% |
Elevation | 2,280 ft (695 m) |
Population (2000) | |
• Total | 52 |
• Density | 1.5/sq mi (0.6/km2) |
GNIS feature ID | 0837845 |
Albany Township is one of sixteen townships in Harlan County, Nebraska, United States. The population was 52 at the 2000 census. A 2006 estimate placed the township's population at 48.[1]
See also
References
- ↑ "Subcounty population estimates: Nebraska 2000-2006" (CSV). United States Census Bureau, Population Division. 2007-06-28. Archived from the original on 18 February 2008. Retrieved 2008-02-26.
External links
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