1990 UEFA European Under-18 Championship
| Tournament details | |
|---|---|
| Host country | Hungary |
| Dates | 24 July - 29 July |
| Teams | 8 |
| Final positions | |
| Champions |
 Soviet Union (6th title) |
| Runners-up |
 Portugal |
| Third place |
 Spain |
| Fourth place |
 England |
| Tournament statistics | |
| Matches played | 10 |
| Goals scored | 25 (2.5 per match) |
The UEFA European Under-18 Championship 1990 Final Tournament was held in Hungary. It also served as the European qualification for the 1991 FIFA World Youth Championship.
Teams
The following teams qualified for the tournament:
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Belgium - England
-
Hungary (host, but still qualified) - Portugal
-
Republic of Ireland - Soviet Union
- Spain
-
Sweden
Quarterfinals
Semifinals
Places 5-8
Places 1-4
Third Place Match
Final
| 1990 UEFA European Under-18 Championship |
|---|
Soviet Union Sixth title |
Qualification to World Youth Championship
The six best performing teams qualified for the 1991 FIFA World Youth Championship.
- England
- Portugal (host)
- Republic of Ireland
- Soviet Union
- Spain
- Sweden